Suppose
a mass m is supported by two ropes, as shown below. One rope extends
horizontally from the wall, and the other rope goes to the ceiling at an angle q from the vertical. Calculate the
tension in each rope.
We begin by making a free-body diagram of the mass m. This is a picture
that isolates the mass from its surroundings, and shows only those forces
acting on the mass. The forces acting on this mass are the tensions in the two
ropes, which we will call T1 and T2, and
its weight mg, which of course points down:
We
will also need to break the T2 vector into x and y
components (the other two force vectors are already on either the x or y
axis). This becomes
Now,
for the total force to add up to zero, all the vectors along the y axis
and all the vectors along the x axis must add up to zero.
1.
Sum of forces in the x-direction equals zero
T2
sin q -T1 = 0
2.
Sum of forces in the y-direction equals zero
T2
cos q -mg = 0
We
now have two equations in two unknowns, T1 and T2
(we are assuming that m and q
are known). The second equation can be solved for T2 to give
This
can be substituted into the first equation, which can then be solved for T1: