Combine the logs using the property:
Expand and rewrite as zero equation.
Upon substituting the solutions into the original equation,
we find that -7 could not be a solution.
Thue, the solution set is S = {0}
Use the property
Apply the arrow rule: Solve for the argument by raising
the base to whatever is on the other side. The direction
of the inequality is kept (not reversed) since the
base is greater than one.
Mathcad is unable to solve the double-sided inequality.
then the other. The solution will be the intersection
of the two intervals.
To avoid division, move the negative term to the other
side.
6. Write as a single logarithm
Answer the following questions with T
(rue) or F
(alse). Note: An incorrect answer will cancel a correct
answer.
___T___ a)
.
___T___ b)
.
___T___ c)
is an increasing function.
___T___ d) The function
has no x-intercept and and y-intercept equal to zero.
___F___ e) The graph of
is the same as the graph of g(x) = x.
___F___ f) The function
is undefined for all x.
___F___ g)
.
___T___ h) Life does not always
give you a second chance.
has no real solution
Mathcad is returning the complex solution as well.
4. If
and
, express
in terms of x and y.
5. Find the value of
b)
Set the factors to zero and solve for x
So, we have only three open intervals:
Choose a point in one of the intervals and substitute
in the inequality to check for sign.
Answer all questions. Show all your work
Cheating in punishable by an F-grade for the course.
1. Find the domain of the functions:
a)
Set the argument greater than zero and solve for x
b) Find the range of f(x) (
do not use the graph)
Start with the range of the exponential function
Multiply by -1 and reverse the inequality
Add 2 to all sides (-
will not be affected).
Rewrite in standard form (small numbers to the left)
by reading the previous inequality from the right.
Choose the point 0 in the first interval and substitute
in the inequality.
Therefore, the point satisfies the inequality and ever
point in that interval in a solution. Now we take every
other interval (take one, leave one). Thus, we skip
the interval (1, 2) and take the interval
. However, the point x = 3 can not be taken because
it is not part of the solution due to the strict inequality.
2. Let
a) Sketch the graph of
As discussed in class, it better to do the shifting
then the reflection in the x-direction, and the
S
reflection then the shifting in the y-direction ( Remember
the rule: S __ | )
Figure 1 illustrates the steps of graphing the function
starting with the graph of
.
Reflect about the y-axis
(Replacing x by -x)
Reflect about the x-axis
(Replacing y by -y)