Find the equation represented by the graph shown below.
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Rewrite the eqn. to the standard form
Solve for x to find the eqns of the right and left sides
of the ellipse.
This is the graph of the right half of a standard ellipse.
Solve for
We can only solve for either
![](OldExamPorblems1481.JPG
)
or
![](OldExamPorblems1482.JPG)
in terms of the other.
Compute the dot product and set it to zero.
Find a nonzero vector that is perpendicular ot the vector
u = < -2, 7>
Find the vertex, focus and the directrix of the parabola
![](OldExamPorblems1515.JPG)
.
For the vectors u, v and w shown in the figure, which
one of the following relations is TRUE?
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You may choose any real number for
To find the point of intersection:
Therefore, the intersection will be in the Quadrant
I only.
The fact that y is under the square root ==> that
y must be positive.
The fact that x is equal to the squre root of something
==> x must be positive.
Therefore, the equation of the ellipse is:
Substitute
![](OldExamPorblems2096.JPG)
in the second equation
Form of the ellipse read from the given foci
Which one of the following is FALSE?
Find the number of solutions of the equation
![](
OldExamPorblems1795.JPG)
over the interval [0, 3
p
/2)
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The zeros of f(x) are obtained by setting f(x) = 0 and
solving for x.
Find the zeros of the function
![](OldExamPorblems1643.JPG
)
in the interval [0, 2
p)
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Find the set of solutions of the equation sin3x = 1.
Find all the solutions of the equation
![](
OldExamPorblems1701.JPG)
,
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Expand the cosine of the difference
Apply cosine to both sides.
Solve the equation
![](OldExamPorblems1765.JPG
)
for x.
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The number of solutions is 4.
--------------------------------
Note:
![](OldExamPorblems1679.JPG)
is not a solution since
![](OldExamPorblems1680.JPG
)
is not defined.
Divide by sin(x) and consider that sin(x) =0 may include
solutions.