
NUCLEAR PROPERTIES
 Interaction between 50 nucleons is 50 ! terms, so we have to have a way to study these interactions.
 mass, radius, density, abundance, decay modes, half lives, reaction modes, cross sections, spin, mag. dipole moment, electric quadrupole moment, excited states.....
 Static Properties : charge, radius, mass ..........
 Dynamic Properties : decay, reaction
 108 nuclides ( >1000 if we consider isotopes )
 Where to find properties of nuclides?!
(Journals, compiled sources (tables))
THE NUCLEAR RADIUS
 The nucleus is approximately spherical Þ nuclear radius.
 2 parameters : 1. Radius 2. Skin thickness
 59Co was studied using neutrons (neutron scattering).
 Why is this diffraction pattern?
Density is changing in the nucleus so we have a diffraction pattern similar to light going through media of different index of refraction n.
 Why the diffraction pattern is not so pronounced?! (no sharp surface).
Nuclear density and nuclear potential have the same spatial dependence. we are measuring distribution of nuclear charge.
The Distribution of Nuclear Charge
 Radiation Scattering Shape of the object
Dimension of the object
 Beams of electrons with energies 100 MeV to 1 GeV are used.
 Diffraction patterns are analyzed and
 Initial wave function
 Electron can be considered as a free particle
 After scattering of the electron and wave function
 The potential is
 Transition probability where
=

 Substituting and integrating over r we get we get the normalized result 
is the distribution of the nuclear charge.

for elastic scattering
q is a function of the scattering angle
 F(q) = form factor using Fourier Transfer
 Notice that the density is almost constant for all nuclei.
 # of nucleons/unit volume constants.
 t is distance from 90% of to 10% of
 Root mean square radius < r^{2 }>^{ }==(R^{2}) for a uniformly charged sphere.
 See other ways of calculating nuclear charge radius in Krane.

r1 = density at small values of r
Re = r at r = r1 / 2
t = surface thickness
 Charge density & matter density.
 It is found that nuclear matter density is the same for all nuclei aside from surface effects.
 t 2.4 fm
 Re 1.07 A 1/3 = r0 A 1/3 fm = mean electromagnetic radius
 nuclear potential radius
R 1.22 A 1/3 fm
THE DISTRIBUTION OF NUCLEAR MATTER
 Interaction between two nuclei due to nuclear force
Nuclear radius rather than Coulomb radius.
 Consider the scattering of particles from (Rutherford Scattering).
 Particles should have enough energy to overcome the Coulomb potential break down of Rutherford’s formula see Fig. 3.11.
 Another method of determining the nuclear radius is decay.
 particle must escape the nuclear potential to the Coulomb potential.
 decay probabilities can be calculated using Schrödinger’s equation.
 Comparison with measured values R
 The charge and matter radius of nuclei are nearly equal to within about 0.1f.
NUCLEAR MASS
 Nucleus has 99.97% of the mass of an atom.
 Old scale (O16) new scale (C12)
C12 = 12.000000 u
E = 931.48 MeV
See tables at the end of KRANE & ENGE practice with a nucleus.
Neutron = 1.008665 u
Proton = 1.007277 u
What happened to the rest of the mass for a nucleus like for example?
MASS AND ABUNDANCE OF NUCLIDES
 Although we need to use nuclear masses in nuclear reactions and decays, tables list the values of neutral atoms only we need a correction.
 The Binding Energy in the nuclear is large.
 For a typical nucleus B.E ^{ } 8 M.eV 8 * 10^{3} of total mass (for atomic B.E ^{ } 1.4*10^{8})
 For quarks the B.E is about 0.99 of the total energy, so 3 quarks of total energy of ~ 300 Ge combine to produce a nucleon of rest energy 1 GeV.
 So it is not possible to separate the discussion of rest mass from binding energy.
 Experimentally how do we measure nuclear masses?
 The old and precise method is through Nuclear Mass Spectrometry.
 Neighboring isotopes differ in mass by approximately 1%.
 Mass Spectroscopes can measure masses to a precision of 10^{6}.
 A Mass Spectrograph has:
Ion Source Velocity Selector Momentum Selector electromagnetic field uniform magnetic field qE = qvB will pass v = E/B_{s}
F_{r}= F_{B}
_{ }  For accuracy we measure the difference between two nearly equal masses (mass doublets). NUCLIDE ABUNDANCES  We can use the mass spectrometer to find the nuclide abundance also by varying E or B (see Fig. 3.14) SEPARATED ISOTOPES  If we set the Mass Spectrometer on a certain mass, we can produce large quantities of it to do experiments. Oak Ridge Nat. Lab sell these isotopes. LASER ISOTOPE SEPARATION  Set one laser to excite only certain atoms (How).A second laser will ionize these atoms only and can be collected using an electric field (Fig. 3.15). BINDING ENERGY
(1)
Or
(2)
What happened to the electron mass in (1) and B of electrons
= Binding energies for electrons 10  100 keV
Neutron Separation Energy (How to find it)
Proton Separation Energy Sp
Þ Similar to atomic ionization energies
 If we plot A vs B/A we notice the following
1. The curve is relatively constant except for light nuclei.
2. B/A 8 MeV to within 10%
3. At A = 60 nuclei are most tight
hence we gain energy by either assembling lighter nuclei into heavier ones (fusion) or by breaking heavier nuclei into lighter nuclei (fission).
Þ Homework (check the above statement)
Fission and fusion can yield energy
 Trying to understand this curve led to semiempirical mass formula.
B/A constant Þ B = av A
 We would expect B µ (A1) (Why)
Þ nucleon interact only with their closest neighbors.
Þ short distance effect ( for the nuclear force )
 B = av A is an overestimate because nucleons on the surface don't contribute the same as inner nucleons, so we have to subtract a term proportional to Surface Area ~ (why & Surface Area is µ R2)
So
B =
We also need a term µ Coulomb interaction or Z (Z1), why ? (since each proton repel all others)
So
B =  ac Z (Z1) / A1/3 (why “ – “for Coulomb)
 We also need a term that favors nuclei along the line Z=N or Z = A/2
 
The further away a nucleus is from Z = N the less bound it is.
 From observing nuclei in nature they found that there are only 4 stable nuclei with odd N and Z
and 167 stable nuclei with even N and Z.
Þ There must be a pairing term d ( other forms exist )
Where
ì ap A3/4 for even N and Z ï d = í 0 for odd A (even Z and odd N or vice versa) ï î  ap A3/4 for odd N and Z

,
,
M(Z, A) = Z m_{H} + N m_{n} – B (Z, A)/ c^{2}^{ }  For constant A This is an equation of a parabola ( See Fig 3.18)  We can find the minimum by differentiating ¶M / ¶Z = 0 