KFUPM-Physics102-032

Dr.Aljalal

Sec07

Sec08

Sec09

Recitation ch 29

Answers at the end

Question 1

The path of a charged particle in a magnetic field, when

its direction of motion is not at right angle to the

magnetic field, will be a:

a helix.

b circle.

c straight line.

d hyperbola.

e parabola.

==============================================

Question 2

An electron that has velocity

v = 3.2*10**7 i m/s

traveling parallel to a uniform magnetic field of strength

2.60*10**(-3) Tesla. The force on the electron is:

[i is the unit vectors in the directions of x]

a 6.1*10**(-15) N.

b 1.4*10**(-15) N.

c 2.3*10**(-15) N.

d 5.0*10**(-15) N.

e zero.

==============================================

Question 3

Particle #1 (of mass m and charge q) and another particle #2

(of mass 3 m and charge q) are accelerated through a common

potential difference V. The two particles enter a uniform

magnetic field B along a direction perpendicular to B. If

particle #1 moves in a circular path of radius r1, then the

radius r2 of the circular path of particle #2 is:

a r1*Sqrt(2).

b r1*Sqrt(6).

c r1*Sqrt(5).

d 2.0*r1.

e r1*Sqrt(3).

==============================================

Question 4

A closed loop has an area of 5.8*10**(-2) m**2 and carries a

current of 3.0 A. It is placed in an external magnetic field,

whose magnitude is 0.50 T, with its dipole moment initially

making an angle of 90 degrees with the external magnetic field.

How much work is done by the magnetic field as it rotates the

loop from its initial orientation to the final orientation where

the dipole moment is aligned with the field ?

a - 0.087 J

b + 0.087 J

c zero

d + 0.042 J

e - 0.042 J

==============================================

Question 5

A straight horizontal length of copper wire is located in a

place where the magnetic field of the earth B = 0.5*10**(-4)T

(see figure 5). What minimum current in the wire is needed

to balance the gravitational force on the wire?

[The linear density of the wire is 60.0 gram/m]

a 1.2*10**4 A into the page.

b 4.3*10**4 A out of the page.

c 1.2*10**4 A out of the page.

d 4.3*10**4 A into the page.

e 3.2*10**4 A into the page.

==============================================

Question 6

A loop of wire carrying a current of 2.0 A is in the shape of a

right-angle triangle with two equal sides, each 15 cm long.

A 0.70-T uniform magnetic field is in the plane of the triangle

and is directed as shown in figure 7.

The magnetic force on side 3 is :

a 0.21 N, into of the page

b 0.21 N, out the page

c zero

d 0.30 N, into the page

e 0.30 N, out of the page

==============================================

Question 7

A charged particle has a speed of 2.03*10**5 m/s, and is circulating

in a plane perpendicular to a uniform magnetic field. If the frequency

of circling is 100 kHz, then the radius of the circle is:

a 0.322 m

b 0.915 m

c 0.753 m

d 1.11 m

e 0.852 m

==============================================

Question 8

Which of the following statements are true?

(I) The magnetic field unit is the tesla.

(II) A magnetic field cannot change the kinetic energy of

a charged particle.

(III) A charged particle moving parallel to a magnetic field

will be deflected.

(IV) The unit of magnetic dipole moment is ampere/meter.

a III, and IV.

b II, and III.

c II, III, and IV.

d I, and II.

e I, III, and IV.

==============================================

Question 9

An electron moving at right angle to a uniform magnetic

field completes a circular orbit in 10**(-8) s. What

is the magnitude of the magnetic field.

a 6.3*10**(-3) T.

b 3.6*10**(-3) T.

c 1.0*10**(-3) T.

d 2.5*10**(-3) T.

e 4.2*10**(-3) T.

==============================================

Question 10

An electron with a kinetic energy of 1.5 keV circles in

a plane perpendicular to a uniform magnetic field. The

radius of the orbit is 20 cm.

Find the magnitude of the magnetic field.

a 4.7*10**(-4) T

b 2.5*10**(-5) T

c 8.4*10**(-4) T

d 6.5*10**(-4) T

e 3.0*10**(-4) T

==============================================

Question 11

An electron moves in the positive x direction, through

a uniform magnetic field B pointing in the negative y

direction, as shown in figure 7.

The magnetic force on the electron is

a in the negative z direction.

b in the negative x direction.

c in the positive z direction.

d in the negative y direction.

e in the positive y direction.

==============================================

Question 12

In figure (9), a loop of wire carrying a current, I, of 3.0 A

is in the shape of a right triangle with two equal sides, each

2.0 m long. A 2.0 T uniform magnetic field is in the plane of

the triangle and is parallel to the hypotenuse. The resultant

torque on the loop is:

a 16 N*m.

b 15 N*m.

c 3 N*m.

d 24 N*m.

e 12 N*m.

==============================================

Question 13

A proton with velocity v = (2.0*10**6) i (m/s) moves

horizontally into a region of space in which there is

an electric field E = (- 5000) j (N/C) and a magnetic

field B. Find the smallest magnetic field such that

the proton will continue to move horizontally undeflected.

(i, j and k are unit vectors in the x, y and z directions,

respectively)

a - 2.5*10**(-3) k (T)

b + 2.5*10**(-3) k (T)

c + 2.5*10**(-3) j (T)

d - 2.5*10**(-3) j (T)

e (1.5 i + 2.5 j)*10**(-3) (T)

==============================================

Question 14

An electron enters a region of uniform electric and

magnetic fields. It is observed that the velocity of

the electron is unaffected.

A possible explanation is that the velocity is:

a perpendicular to B and parallel to E

b perpendicular to both E and B

c perpendicular to E and parallel to B

d parallel to E and has magnitude E/B

e parallel to B

==============================================

Question 15

A wire 72 cm in length has a mass of 15 g. It is suspended

by a pair of flexible leads in a magnetic field B = 0.54 T

pointing out of the page, as shown in figure 8.

What current must exist in the wire for the tension in

the supporting leads to be zero ?

a 0.039 A from Q to P

b 0.49 A from P to Q

c 0.49 A from Q to P

d 0.38 A from Q to P

e 0.38 A from P to Q

==============================================

Question 16

At one instant an electron is moving with a velocity:

->

v = (5*10**5 i + 3*10**5 j) m/s

->

in a magnetic field of B = (0.8 i) T.

At that instant the magnetic force on the electron is:

(i, j, and k are the unit vectors in the directions of x,

y, and z, respectively).

a - 3.8*10**(-14) k N.

b 7.5*10**(-14) j N.

c 3.8*10**(-14) k N.

d 6.4*10**(-14) k N.

e - 6.4*10**(-14) k N.

==============================================

Answers

1 a

2 e

3 e

4 b

5 a

6 a

7 a

8 d

9 b

10 d

11 c

12 e

13 a

14 b

15 d

16 c