ME – 308 – MACHINE DESIGN II
Fall Semester. 2000 – 2001 (001)
Allowable
bearing pressure = 2 X (Bearing pressure in table 1)
Starting
Friction = 1.3 X (Running Friction)
2. Different parts of a Screw Jack
Screw
Nut
Turning Lever
Base
Cup
Retaining Pins
Assume the material for the
screw : AISI Steel 1040 CD
Assume the material for the
nut : Bronze
Reasons for selecting AISI 1040 CD for the screw and Bronze for the Nut
It has a good surface finish
which improves fatigue strength
It can be machined easily
and resists wear.
Cold Drawing results in a
large increase in yield strength, ultimate strength and hardness.
Bronze
It has high strength and
high wear resistance
It is used with the nut to
reduce friction with the screw
Assuming that
it is a Johnson’s Column with central loading and assuming that both ends are
rounded or pivoted:
where
is Critical Load
is Radius of Gyration
is Unsupported Length of the column
=
=
where
= Root Diameter
= Pitch Diameter
Using equation
(3 – 58) and equation (3 – 56) check for
Johnson’s column.
Sometimes when
the load is large or the friction is low, the load will lower itself by causing
the screw to spin without any external effort.
If this
doesn’t happen then it is said to be self locking.
Condition for
self locking:
Select from Table –2.
Finding the Torque to raise the load:
is the Torque required to overcome the thread friction and to
raise the load.
The area of the screw, which is at the root diameter, is subjected to a biaxial stress caused by both the compressive stresses on the screw and the shearing stress caused by the applied torque.
Max. Shear Stress Theory:
where
(Check)
Distortion Energy Theory:
(Check)
Select the largest as a safe root
diameter.
Efficiency of the power screw: