Bearing Selection
Decide whether to use deep groove ball bearing or angular contact bearing.
Calculate resultant reactions at bearing A
Depending on the type of application, select bearing life (no. of hours) from Table 11-4 and Load-Application factor from Table 11-5.
Assume a reliability of 0.9
Assume a rating life of one million revolutions as the base value.
Using following equation from the text book, calculate the rated force for each bearing:
Where:
is the Catalog Load Rating
is the Design Load
is the Design Life in Hours
is the Design Speed (given in rpm)
is the Rated Life = 106 rev.
R is the Reliability
a for ball bearing = 3
For the values of , use the values of the resultant reaction calculated for locations A ,
To calculate C, use the following equation:
Where:
A.F. is the Load-application Factor.
Select Bearings for the bearing locations A on the shaft using Table 11-2. Use the value of C, calculated above to select the bearing and note down all bearing data.
NOTE:
Convert to rev. before solving the equation
The bearing shoulder diameter should be greater than the diameter calculated from fatigue analysis and take bearing shoulder diameter as
KEY DESIGN
· When the diameter of a gear is more than double that of the shaft diameter, it is usually keyed to the shaft.
· Keys are generally made of cold-drawn low carbon steel.
· Select suitable CD steel from (Table E-20) of Appendix.
· Compare yield strength of the shaft with the yield strength of the key material and use weakest of the two in calculations,
· With diameter calculated, select square keys for gear 3 from (Table 8-20).
Now we need to calculate length of the key.
Keys generally have two types of failures:
(1) Shear Failure: Keys of the shaft and hub exert equal and opposite forces of value F, these forces attempt to shear the key at the radius of the shaft.
Shear area =
Shear force , where T = torque
Using distortion –energy theory
Yield strength in shear,
, where n = factor of safety
(2) Bearing or Crushing Failure: Keys can suffer permanent compressive deformation where it contacts the keyways in the shaft and hub.
· Since one-half of the key is in the hub and one-half is in the shaft, as measured at the side of the keyway, the bearing area in each is .
· The line of action of the force between the hub and the key would be a little above, and force between the shaft and the key would be a little below from the force acting at the surface of the shaft.
· Because of inherent inaccuracies in the analysis and the small difference involved, the moment arm of the force is taken as .
Where is the yield strength in compression.
· Use larger of the length obtained from two types of failure.
· Generally key lengths fall within the following ranges:
·
· If key length is less than , then take key length equal to .
· If the required key length is greater than , consider using two keys, apart.